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level: Test for Anions

Questions and Answers List

level questions: Test for Anions

QuestionAnswer
How to test for Halide Ions? [Chloride, Bromide and Iodide Ions]-First: Add some Dilute Nitric Acid [HNO³] followed with Silver Nitrate Solution [AgNO³] -If it was the Chloride Ions you were Testing, you would get a White Precipitate of Silver Chloride [As because they React] -If it was the Bromide Ions you were Testing, you would get a Cream Precipitate of Silver Bromide [As because they React] -If it was the Iodide Ions you were testing, you would get a Yellow Precipitate of Silver Iodide [As because they React]
In the Test of Halide Ions, why is Nitric Acid added First?-This is so that no Carbonate Ions can Form. -This is important because they make a Pale Precipitate with the Silver Nitrate which wouldn't be Helpful -Hydrochloric Acid is useless, because your adding Chloride Ions
How to test for Carbonates?-First add Barium Chloride Solution to whatever Solution you want to decipher -If Carbonate Ions are Present, then a White Precipitate will appear, of Barium Carbonate -Then add in some Hydrochloric Acid -If Carbonate Ions are Present, then you will see a Fizz, due to the Carbonate Reacting with the Acid to make Carbon Dioxide [Use Test for Carbon Dioxide to Prove it] -When all the Barium Carbonate has been Reacted, a Colourless Solution will appear, containing Ba²+
Give the Formula for the: Test for Carbonates:Barium Carbonate + Acid --> Barium Ions + Carbon Dioxide + Water BaCO³ + 2H+ ---> Ba²+ + CO² + H²O
Test for Sulphate Ions goes like...?-First add Barium Chloride to the Solution you want to Decipher -If Sulphate Ions are Present, then a White Precipitate of Barium Sulphate will be Present -Then add Dilute Hydrochloric Acid to it -What will happen next, will be Nothing, because Barium Sulphate will Not React with the Hydrochloric Acid, so the White Precipitate will not Vanish -[This simply means you have Sulphate Ions, and not Carbonate Ions]
Give the Formula for the: Test for Sulphate Ions:Barium Ions + Sulphate Ions --> Barium Sulphate Ba₂+ + SO₄ ₂- ---> BaSO₄