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Unit 3 Part 1 - Chapter 14 (Mendelian Genetics) - DAY 1

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Question:

Epistasis

Author: AMRIT KAUR



Answer:

- Some traits may be determined by two or more genes​- In epistasis, one gene affects the phenotype of another due to interaction of their gene products​ - [ IN FANCY WORDS: In epistasis, expression of a gene at one locus alters the phenotypic expression of a gene at a second locus​ ] - For example, in Labrador retrievers and many other mammals, coat color depends on two genes ​ - One gene determines the pigment color (with alleles B for black and b for brown) ​ - The other gene (with alleles E for color and e for no color) determines whether the pigment will be deposited in the hair - If heterozygous black labs (genotype BbEe) are mated, we might expect the dihybrid F2 ratio of 9:3:3:1​ - However, a Punnett square shows that the phenotypic ratio will be 9 black to 3 chocolate to 4 yellow labs ​- Epistatic interactions produce a variety of ratios, all of which are modified versions of 9:3:3:1​


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- Some traits may be determined by two or more genes​- In epistasis, one gene affects the phenotype of another due to interaction of their gene products​
- [ IN FANCY WORDS: In epistasis, expression of a gene at one locus alters the phenotypic expression of a gene at a second locus​ ]
- For example, in Labrador retrievers and many other mammals, coat color depends on two genes
​     - One gene determines the pigment color (with alleles B for black and b for brown)
​     - The other gene (with alleles E for color and e for no color) determines whether the pigment will be  deposited in the hair
     - If heterozygous black labs (genotype BbEe) are mated, we might expect the dihybrid F2 ratio of 9:3:3:1​
     - However, a Punnett square shows that the phenotypic ratio will be 9 black to 3 chocolate to 4 yellow labs
​- Epistatic interactions produce a variety of ratios, all of which are modified versions of 9:3:3:1​
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