How many moles of copper will be produced if we used 0.5 moles of copper sulphate and 1 mole of magnesium? Calculate the mass of copper produced. Ar Cu = 63.5 Ar S = 32 Ar O = 16 Ar Mg = 24 CuSO4 + Mg -> MgSO4 + Cu

CuSO4 + Mg -> MgSO4 + Cu 1) We only have 0.5 moles of copper sulphate so its the limiting reactant 2) If there is only 0.5 moles of copper then there will only be 0.5 moles of copper 3) To work out mass: mass = moles x Ar (relative atomic mass) - so 0.5 x 63.5 = 31.75g