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MCPH (BOTANY)

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Question:

CALVIN CYCLE (STEP-BY-STEP) (THIRD STEP AFTER LIGHT DEPENDENT REACTION)

Author: Dwight Obillos



Answer:

-Carbon Fixation- 1) Carbon Dioxide attaches to RuBP. As a result, it will produce 6 Carbon Atoms. These atoms will be split into two, 3 Carbon Atoms each called PGA. (2 PGAs) (6 cycles produces 12 PGA) In the complete(6) cycle, it will be 6 carbon dioxide and 6 RuBP, which will produce 12 molecules of PGA -Carbon Reduction- 2) Since there are 12 molecules of PGA, it use 12 molecules of ATP and NADPH. In total, it will produce 12 molecules G3P 3) 10 molecules of G3P is used to generate 6 molecules of RuBP 4) The remaining 2 molecules are used to produce Glucose or Fatty Acids or Glycerol -Regeneration of RuBP- 5) Since there are 6 molecules RuBPs, it will use 6 molecules of ATP


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-Carbon Fixation-
1) Carbon Dioxide attaches to RuBP. As a result, it will produce 6 Carbon Atoms. These atoms will be split into two, 3 Carbon Atoms each called PGA. (2 PGAs) (6 cycles produces 12 PGA)

In the complete(6) cycle, it will be 6 carbon dioxide and 6 RuBP, which will produce 12 molecules of PGA 

-Carbon Reduction-
2) Since there are 12 molecules of PGA, it use 12 molecules of ATP and NADPH. In total, it will produce 12 molecules G3P 

3) 10 molecules of G3P is used to generate 6 molecules of RuBP 
4) The remaining 2 molecules are used to produce Glucose or Fatty Acids or Glycerol

-Regeneration of RuBP-
5) Since there are 6 molecules RuBPs, it will use 6 molecules of ATP
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