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From course:

PHARMACEUTICAL INORGANIC CHEMISTRY LAB (1ST SEMESTER)

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Question:

Test for Aluminum ion

Author: Dwight Obillos



Answer:

A) Al³ + NH4OH → Al(OH)3 + NH4 forms gelatinous precipitate of aluminum hydroxide B) The precipitate formed in the presence of hydrochloric acid is caused by the creation of soluble aluminum chloride. Al(OH)3 + 3HCl → Al Cl3 + 3H2O C) Aluminum chloride from the solution reacts with ammonium hydroxide to form aluminum hydroxide precipitate, which absorb blue color from solution to form an insoluble complex AlCl3 + 3NH5OH → 3NH4Cl +Al(OH)3


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